Evaluate 106 3 by using suitable identity
WebQ127 Evaluate (106)^3 using a suitable Identity Evaluate 106 3 Evaluate 106 whole cube - YouTube More Questions on Algebraic... WebSolution: Using algebraic Identities, (x + a) (x + b) = x 2 + (a + b)x + ab (a + b) (a - b) = a 2 - b 2 (i) 103 × 107 Identity: (x + a) (x + b) = x 2 + (a + b)x + ab 103 × 107 = (100 + 3) (100 + 7) Substituting x = 100, a = 3, b = 7 in the above identity, we get = (100) 2 + (3 + 7) (100) + (3) (7) = 10000 + 1000 + 21 = 11021 (ii) 95 × 96
Evaluate 106 3 by using suitable identity
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WebUsing suitable identity, evaluate the following : 101 × 102 Solution: Given, 101 × 102 We have to evaluate the given expression using a suitable identity. 101 = 100 + 1 102 = 100 + 2 101 × 102 = (100 + 1) × (100 + 2) Using algebraic identity, (a + b) (a + c) = a² + ac + ab + bc = a² + a (b + c) + bc WebMar 22, 2024 · Transcript Example 17 Evaluate 105 × 106 without multiplying directly. 105 × 106 = (100 + 5) × (100 + 6) Using Identity (x + a) (x + b) = x2 + (a + b)x + ab, where x = 100 , a = 5, b= 6, = (100)2 + (5 …
WebMar 28, 2024 · Ex 2.5, 7 Evaluate the following using suitable identities: (i) (99)3 We write 99 = 100 – 1 (99)3 = (100 − 1)3 Using (a – b)3 = a3 – b3 – 3ab (a – b) Where a = 100 & b = 1 = (100)3 − (1)3 − 3 (100) (1) (100 − 1) … WebMar 31, 2024 · Evaluate using suitable identities 102 × 106. LIVE Course for free. Rated by 1 million+ students Get app now ... ← Prev Question Next Question →. 0 votes . 5.3k views. asked Mar 31, 2024 in Algebraic Expressions by Mohini01 (67.9k points) Evaluate using suitable identities. 102 × 106. algebraic expressions; class-8; Share It On …
WebDec 31, 2024 · Evaluate (106)3 using proper identity. 2 See answers Advertisement Advertisement Saaransh07 Saaransh07 Answer: 1191016. Step-by-step explanation: ... factorise by using suitable identity 3a⁴b-24ab⁴ and show it's identity what identity are we going to used to find x³/8+216y³
WebAnswer (Detailed Solution Below) Option 3 : 39,964 India's Super Teachers for all govt. exams Under One Roof FREE Demo Classes Available* Enroll For Free Now Detailed Solution Download Solution PDF Given: Expression = 194 × 206 Concepts used: a 2 – b 2 = (a + b) × (a – b) Calculation: Expression = 194 × 206 194 × 206 = (200 – 6) × (200 + 6)
WebThe p660 form absorbs red light and is converted to the p73o form believed to induce a biological response. The P 7 3 0 form absorbs far-red and is converted to the inactive P 6 6 0 form. The P 7 3 0 form kept in the dark reverts to the P 6 6 0 form (Hendricks 1959). The action spectrum for photolability is seen in the lower part of Figure 9. dt200eu ninjaWebSep 16, 2024 · Using suitable identity evaluate 106^3-94^3 See answers Advertisement siddhartharao77 Given, 106 ^3 - 94 ^3 can be written as = (100+6)^3 - (100-6)^3 We know that (a+b)^3 - (a-b)^3 = 2b (3a^2 + b^2) = 2 * 6 (3 (100)^2 + (6)^2) = 12 (30000 + 36) = 360432 Hope this helps! thank u Advertisement Shobana13 Hi friend, Here is the … dt200 ninjaWebOct 30, 2014 · Find the value of (106)3 - (94)3 using suitable identity Share with your friends 3 Follow 1 Varun.Rawat, Meritnation Expert added an answer, on 31/10/14 106 3 - 94 3 = 100 + 6 3 - 100 - 6 3 = 2 × 6 6 2 + 3 100 2 as, a + b 3 - a - b 3 = 2 b b 2 + 3 a 2 = 12 36 + 30000 = 12 × 30036 = 360432 This conversation is already closed by Expert dt25 suzuki motorWebUsing suitable identity, evaluate 52 × 53. Q. Evaluate 108 × 106 using suitable identity. Q. Using suitable identity, evaluate 136 ... dt201 ninjaWebClick here👆to get an answer to your question ️ Evaluate the following using suitable identities. (105)^3. Solve Study Textbooks Guides. Join / Login >> Class 9 >> Maths ... dt3001-u8-m-saWebUsing suitable identities, evaluate the following: 104×97. Q. Evaluate the following products without multiplying directly: (i) 103×107. (ii) 95×96. (iii) 104×96. Q. Evaluate the … dt201c ninjaWebMar 22, 2024 · Example 23 Evaluate each of the following using suitable identities: (104)3 We write 104= 100 + 4 (104)3 = (100 + 4)3 Using (a + b)3 = a3 + b3 + 3ab(a + b) Where a = 100 & b = 4 = (100)3 + (4) 3 + … dt250 ninja